The ages of 3 men are in the ratio 3:4:5 if the difference between the ages of the oldest and youngest is 18 years. Find the sum of the ages of the three men.
Let the ages of the three men be 3x, 4x, and 5x.
We know that 5x - 3x = 18 (the difference between the ages of the oldest and youngest is 18 years).
Simplifying this, we get 2x = 18, which means x = 9.
So, the ages of the three men are 27, 36, and 45.
The sum of their ages is 27 + 36 + 45 = 108.
Therefore, the sum of the ages of the three men is 108.
We are given that the ages of 3 men are in the ratio 3:4:5. Let's assume the common ratio is x.
So, the ages of the three men can be written as 3x, 4x, and 5x.
We are also given that the difference between the ages of the oldest and youngest is 18 years.
So, 5x - 3x = 18
Simplifying the equation, we have:
2x = 18
Dividing both sides of the equation by 2, we find:
x = 9
Now, we can substitute the value of x back into the ratios:
Therefore, the ages of the three men are 3x = 3(9) = 27, 4x = 4(9) = 36, and 5x = 5(9) = 45.
The sum of the ages of the three men is 27 + 36 + 45 = 108.
So, the sum of the ages of the three men is 108 years.