Use the equations below:
P=mv
Ek=1/2mv^2
2) A linear air track can be used to investigate collisions. Two trolleys or “gliders” are supported on a cushion of air. A glider of mass 0.30kg is stationary in the middle of the track. A second glider of mass 0.25kg and velocity of 0.20ms-1 collides with the first glider and they stick together.
You may assume that this collision is perfectly elastic.
A) What is meant by a “perfectly elastic” collision?
B) Calculate the velocity of the glider combination immediately after the collision.
6 marks
please help with B
is it 0.5 * 0.2= 0.11
then 0.11=1/0.55*0.20^2 though i dont think that makes much sense
please use full words and no symbols and lay it out with steps clearly fullwords pklease
Please pick ONE screenname and keep it. Playing games with screennames is not helpful, nor will it get you help any sooner!
You are missing the point. Conservation of Momentum applies, that is the point.
for the system:
initial momentum=final momentum
.25*.2+.25*0=(.25+.25)V
V=.1m/s
0.25 x 0.2+ 0.25 x 0.2 = (0.25+0.25)V
V= 0.1m/s
Is this what u meant because what you wrote is confusing
also i think it is supposedto be 0.25 x 0.2+ 0.3 x 0 = (0.25+0.3)V as one of the trolley is 0.3kg so am i right?
b=0.05
a=0.55v
so 0.05=0.55v
0.05/0.55= 0.0909..
i mean the momentum bef and aft with those letter just to be clear and help
To calculate the velocity of the glider combination immediately after the collision in a perfectly elastic collision, you need to use the principles of conservation of momentum and conservation of kinetic energy.
Step 1: Determine the initial momentum of both gliders.
The momentum (P) of an object is calculated by multiplying its mass (m) by its velocity (v). Since the first glider is stationary, its initial momentum is 0 kg⋅m/s. The second glider has a mass of 0.25 kg and a velocity of 0.20 m/s. Therefore, its initial momentum is P = (0.25 kg) * (0.20 m/s).
Step 2: Determine the total mass of the glider combination.
Since the two gliders stick together after the collision, their masses are combined. The total mass of the glider combination is the sum of the individual masses: 0.30 kg + 0.25 kg.
Step 3: Apply the principles of conservation of momentum and conservation of kinetic energy.
In a perfectly elastic collision, both momentum and kinetic energy are conserved. Mathematically, this can be expressed as:
Conservation of momentum: Initial momentum = Final momentum
Conservation of kinetic energy: Initial kinetic energy = Final kinetic energy
Since the initial momentum of the glider combination is 0 kg⋅m/s (since the first glider was stationary), the final momentum of the glider combination must also be 0 kg⋅m/s.
Using these principles, you can set up the following equation:
(0.25 kg * 0.20 m/s) + (0 kg * 0 m/s) = (final mass of glider combination) * (final velocity of glider combination)
Step 4: Solve for the final velocity of the glider combination.
Substitute the total mass of the glider combination (0.30 kg + 0.25 kg) and solve for the final velocity. Add the masses and divide both sides of the equation by the total mass to isolate the final velocity:
(0.25 kg * 0.20 m/s) = (0.30 kg + 0.25 kg) * (final velocity of glider combination)
0.05 kg⋅m/s = (0.30 kg + 0.25 kg) * (final velocity of glider combination)
Divide both sides of the equation by (0.30 kg + 0.25 kg) to solve for the final velocity:
(final velocity of glider combination) = 0.05 kg⋅m/s / (0.30 kg + 0.25 kg)
Now, calculate the numerical value.
(final velocity of glider combination) = 0.05 kg⋅m/s / 0.55 kg
(final velocity of glider combination) = 0.0909 m/s
Therefore, the velocity of the glider combination immediately after the collision is approximately 0.0909 m/s.