What is the result of c6h5ch2cooh +H^+/KMnO4
To determine the result of the reaction between C6H5CH2COOH (benzylacetic acid) and H+/KMnO4 (acidic potassium permanganate), we need to understand the potential oxidation and reduction reactions involved.
In this case, KMnO4 acts as an oxidizing agent, while C6H5CH2COOH is the reducing agent. The Mn in KMnO4 can be reduced from an oxidation state of +7 to +2 or +4, depending on the conditions.
To get the result of the reaction, it is necessary to balance the equation by adjusting the number of reactant and product molecules.
The balanced equation for the reaction between C6H5CH2COOH and H+/KMnO4 is as follows:
C6H5CH2COOH + 2KMnO4 + 3H2SO4 → 2CO2 + 2MnSO4 + 2K2SO4 + 8H2O
Thus, the products of the reaction are carbon dioxide (CO2), manganese(II) sulfate (MnSO4), potassium sulfate (K2SO4), and water (H2O).
It is important to note that this reaction usually requires high temperatures and is typically carried out under acidic conditions. Additionally, the stoichiometry may vary depending on the specific reaction conditions and the desired outcome.