Seven bills add up to $73.00 --no change and no one dollar bills
4 - $2
1 - $5
1 - $10
1 - $50
Four $2 bills = $8
One $5 bill = $5
One $10 = $10
One $50 = $50
To solve this problem, we need to find the combination of seven bills that adds up to $73.00.
Since we are told there are no change and no one-dollar bills, we can assume that the bills used are only in denominations of $2, $5, $10, $20, $50, and $100.
We can start by trying different combinations of bills until we find one that adds up to $73.00.
Let's go through the possible combinations:
1. Seven $10 bills: 7 x $10 = $70. This combination falls short.
2. Six $10 bills and one $2 bill: (6 x $10) + $2 = $62 + $2 = $64. This combination falls short.
3. Five $10 bills and two $2 bills: (5 x $10) + (2 x $2) = $50 + $4 = $54. This combination falls short.
4. Four $10 bills and three $2 bills: (4 x $10) + (3 x $2) = $40 + $6 = $46. This combination falls short.
5. Three $10 bills and four $2 bills: (3 x $10) + (4 x $2) = $30 + $8 = $38. This combination falls short.
6. Two $10 bills, three $5 bills, and two $2 bills: (2 x $10) + (3 x $5) + (2 x $2) = $20 + $15 + $4 = $39. This combination falls short as well.
7. One $10 bill, five $5 bills, and one $2 bill: ($10) + (5 x $5) + $2 = $10 + $25 + $2 = $37. This combination also falls short.
8. Three $5 bills and four $2 bills: (3 x $5) + (4 x $2) = $15 + $8 = $23. This combination falls far too short.
Based on our calculations, there doesn't seem to be a combination of seven bills that adds up exactly to $73.00, given the constraints.
It's possible that there may be an error or missing information in the question or that the solution is not achievable with the given conditions. However, based on the information provided, we cannot find a valid solution.