A money envelope contains five $10 bills, ten $20 bills, and fifteen $50 bills. Sandra randomly selects two bills without returning the first bill. What is the probability of getting a $10 bill then a $50 bill? Write your answer in the simplest form of fraction.(1 point)
The probability of drawing a $10 bill on the first draw is 5/30 (since there are 5 $10 bills out of a total of 30 bills). After removing one $10 bill, there are 4 $10 bills left out of 29 total bills. The probability of drawing a $50 bill on the second draw, given that a $10 bill was drawn on the first draw, is 15/29. Therefore, the probability of getting a $10 bill then a $50 bill is:
(5/30) * (15/29) = 25/174
Answer: 25/174
incorrect
To solve this problem, we need to determine the probability of selecting a $10 bill first, and then a $50 bill second.
Step 1: Calculate the probability of selecting a $10 bill first.
There are a total of 5 $10 bills out of 30 bills in the envelope. Since we are not putting the first bill back after selection, there will be 29 bills remaining for the second selection. Therefore, the probability of selecting a $10 bill first is 5/30.
Step 2: Calculate the probability of selecting a $50 bill second.
After the first bill is selected, there will be 29 bills remaining in the envelope. Out of these, there are 15 $50 bills. Therefore, the probability of selecting a $50 bill second is 15/29.
Step 3: Multiply the probabilities from Step 1 and Step 2.
To find the probability of both events occurring, we need to multiply the probabilities from Step 1 and Step 2: (5/30) * (15/29) = 75/870.
Therefore, the probability of randomly selecting a $10 bill first, and then a $50 bill second, without returning the first bill, is 75/870 (or simplified, 5/58).
To find the probability of getting a $10 bill followed by a $50 bill, we need to calculate the probability of each event occurring and then multiply them together.
First, let's determine the probability of selecting a $10 bill. There are a total of 5 $10 bills and 30 bills in total (5 $10 bills + 10 $20 bills + 15 $50 bills), so the probability of selecting a $10 bill on the first draw is 5/30 or 1/6.
After selecting a $10 bill, we have one less $10 bill and 29 bills in total. Now we need to calculate the probability of selecting a $50 bill. There are a total of 15 $50 bills, so the probability of selecting a $50 bill on the second draw is 15/29.
To find the overall probability, we multiply the probabilities of the two events together:
(1/6) * (15/29) = 15/174
Therefore, the probability of getting a $10 bill followed by a $50 bill is 15/174.