Let f(x)=6x−1 and g(x)=3−x2. Evaluate the following:
1. f(g(0))
first do g(0):
3-(0)2 = 3
then do f(3) since 3 was the answer to g(0):
6(3)-1 = 8
i meant 17 for the answer, not 8
To evaluate f(g(0)), we need to substitute the value of 0 into the function g(x) first, then take the result and substitute it into the function f(x).
Let's start by finding g(0).
g(x) = 3 - x^2
Substituting x = 0:
g(0) = 3 - (0)^2
= 3 - 0
= 3
Now that we have g(0) = 3, we can substitute this value into the function f(x).
f(x) = 6x - 1
Substituting x = 3:
f(g(0)) = f(3)
= 6(3) - 1
= 18 - 1
= 17
Therefore, f(g(0)) is equal to 17.