If the side of a square is doubled in size to 8", by what percent did it's area increase?
area square=s^2
if doubled, area= (2s)^2=4s^2
percent= changeInArea/area * 100
= 400/1=four hundred percent
If the result is 400% of the original 100%, then the increase is 300%
+100% = doubled
+200% = tripled
+300% = quadrupled
That is always confusing and the thing to remember is that doubling is 100% increase.
To find the percentage increase in the area of a square when its side is doubled, you can follow these steps:
1. Determine the original side length of the square. In this case, it is 4 inches since it has been doubled to 8 inches.
2. Calculate the original area of the square by squaring the side length. In this case, 4 inches multiplied by 4 inches equals 16 square inches.
3. Calculate the final area of the square by squaring the new side length. In this case, 8 inches multiplied by 8 inches equals 64 square inches.
4. Find the difference between the final area and the original area. In this case, the difference is 64 square inches minus 16 square inches equals 48 square inches.
5. Divide the difference by the original area, and then multiply it by 100 to find the percentage increase. In this case, 48 square inches divided by 16 square inches equals 3. Multiplying this by 100 gives you a percentage increase of 300%.
Therefore, the area of the square increased by 300% when the side length was doubled from 4 inches to 8 inches.