The sides of a square all have a side length of y . Write a simplified area function in terms of y for a rectangle whose length is twice the side length of the square and whose width is 2 units longer than the side length of the square. Part A: Express both the length and the width of the rectangle as a function of a side of the square. (1 point) Responses Length: L(s)=2y Width: W(s)=y+2 Length: cap l times s is equal to 2 y Width: cap w times s is equal to y plus 2 Length: L(s)=2+y Width: W(s)=2y Length: cap l times s is equal to 2 plus y Width: cap w times s is equal to 2 y Length: L(s)=y2 Width: W(s)=2y Length: cap l times s is equal to y squared Width: cap w times s is equal to 2 y Length: L(s)=y2 Width: W(s)=y+2
The correct answer is:
Length: L(s) = 2y
Width: W(s) = y + 2
Part B: Write a function to represent the area of the rectangle in terms of the sides of the square. (1 point) Responses A(s)=2y3+2y2 cap A times s is equal to 2 y cubed plus 2 y squared A(s)= 2y2+4y A(s)= 2y2+4y A(s)=6y+4 cap A times s is equal to 6 y plus 4 A(s)=2y2+4 cap A times s is equal to 2 y squared plus 4 A(s)=3y+2
The correct answer is:
A(s) = 2y^2 + 4y