As physics

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Use the equations below:
P=mv
Ek=1/2mv^2
2) A linear air track can be used to investigate collisions. Two trolleys or “gliders” are supported on a cushion of air. A glider of mass 0.30kg is stationary in the middle of the track. A second glider of mass 0.25kg and velocity of 0.20ms-1 collides with the first glider and they stick together.
You may assume that this collision is perfectly elastic.
A) What is meant by a “perfectly elastic” collision?
B) Calculate the velocity of the glider combination immediately after the collision.

6 marks


please help with B


is it 0.5 * 0.2= 0.11
then 0.11=1/0.55*0.20^2 though i dont think that makes much sense

please use full words and no symbols and lay it out with steps clearly fullwords pklease

  • cake/cylinder/tricky -

    Please pick ONE screenname and keep it. Playing games with screennames is not helpful, nor will it get you help any sooner!

  • As physics -

    You are missing the point. Conservation of Momentum applies, that is the point.
    for the system:
    initial momentum=final momentum
    .25*.2+.25*0=(.25+.25)V
    V=.1m/s

  • As physics -

    0.25 x 0.2+ 0.25 x 0.2 = (0.25+0.25)V
    V= 0.1m/s
    Is this what u meant because what you wrote is confusing

  • As physics -

    also i think it is supposedto be 0.25 x 0.2+ 0.3 x 0 = (0.25+0.3)V as one of the trolley is 0.3kg so am i right?

  • As physics -

    b=0.05
    a=0.55v
    so 0.05=0.55v
    0.05/0.55= 0.0909..

  • As physics -

    i mean the momentum bef and aft with those letter just to be clear and help

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