# As physics

posted by cake

Use the equations below:
P=mv
Ek=1/2mv^2
2) A linear air track can be used to investigate collisions. Two trolleys or “gliders” are supported on a cushion of air. A glider of mass 0.30kg is stationary in the middle of the track. A second glider of mass 0.25kg and velocity of 0.20ms-1 collides with the first glider and they stick together.
You may assume that this collision is perfectly elastic.
A) What is meant by a “perfectly elastic” collision?
B) Calculate the velocity of the glider combination immediately after the collision.

6 marks

is it 0.5 * 0.2= 0.11
then 0.11=1/0.55*0.20^2 though i dont think that makes much sense

please use full words and no symbols and lay it out with steps clearly fullwords pklease

1. Writeacher

Please pick ONE screenname and keep it. Playing games with screennames is not helpful, nor will it get you help any sooner!

2. bobpursley

You are missing the point. Conservation of Momentum applies, that is the point.
for the system:
initial momentum=final momentum
.25*.2+.25*0=(.25+.25)V
V=.1m/s

3. cake

0.25 x 0.2+ 0.25 x 0.2 = (0.25+0.25)V
V= 0.1m/s
Is this what u meant because what you wrote is confusing

4. cake

also i think it is supposedto be 0.25 x 0.2+ 0.3 x 0 = (0.25+0.3)V as one of the trolley is 0.3kg so am i right?

5. cake

b=0.05
a=0.55v
so 0.05=0.55v
0.05/0.55= 0.0909..

6. cake

i mean the momentum bef and aft with those letter just to be clear and help

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