Math check

Decide whether each equation has one, no solutions, or infanatly many solutions

1.) 2(x - 3) = 2x

One solution
no solutions
many solutions
infinatly many solutions

2.) 3(y - 3?) = 2y - 9 + y

One solution
no solutions
many solutions
infinatly many solutions

3.)10x - 2 - 6x = 3x -2 + x

One solution
no solutions
infinatly many solutions

4.) 4(x + 3) + 2x = x - 8

One solution
no solutions
infinatly many solutions

MY ANSWERS

1. D
2. A
3. B
4. C

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asked by Josh
  1. 1. Actually it's B.
    Expanding,
    2(x - 3) = 2x
    2x - 6 = 2x
    -6 = 0
    Note that if you get an answer like this (constant = zero), there is no solution.

    2. It's D. (btw I don't know why you put question mark beside 3)
    Expanding,
    3(y - 3) = 2y - 9 + y
    3y - 9 = 3y - 9
    or
    0 = 0
    Note that if you get an answer like this (zero = zero), there are infinite solutions.

    3. It's C.
    Expanding,
    10x - 2 - 6x = 3x -2 + x
    4x - 2 = 4x - 2
    0 = 0
    (infinite solutions)

    4. It's A.
    Expanding,
    4(x + 3) + 2x = x - 8
    4x + 12 + 2x = x - 8
    6x + 12 = x - 8
    5x = -20
    x = -4
    (one solution)

    I guess you have to study these topics.
    Hope this helps :3

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    posted by Jai
  2. Check your answers again.

    1. -3 = 0?

    2. 3y-9 = 3y -9 (identity)

    3. 4x-2 = 4x-2 (identity)

    4. 6x+12 = x-8

    5x = -20

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    posted by PsyDAG
  3. Thank you Jai, I understand it all perfectly now.

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    2. 👎 0
    posted by Josh
  4. 7x+3=7x+b

    1. 👍 0
    2. 👎 0
    posted by Bibi
  5. 1)B
    2)C
    3)C
    4)A

    For the students that do not have 4 options for answers.

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