Need help on these questions!
Find the slope of each line.
1. Y=x+1
Solve the equations.
2. -6+x/2=2
Simplify each expression.
3. -4(5n-5)+6(1-7n)
y = m x + b where m is slope
so y = 1 x + 1
means slope = m = 1
multiply both sides by 2
-12 + x = 4
add 12 to both sides
x = 16
first multiply out
-20 n + 20 + 6 - 42 n
then combine like terms
-22 n + 26
1. So you know that the slope intercept form is y=mx+b, right. And m is the slope. So in this case there is no straight out coefficient, but x is also equal to 1x. Therefore one is your slope.
2. So first bring -6 to the opposite side of the equation by adding 6 to each side. You are left with x/2 = 8. Then you want to separate x, so you multiply each side by two to get rid of the denominator. This leaves x being 16.
3. So in order of PEMDAS you would multiply first. So begin by distributing the -4 to make the left side be -20n + 20. Then distribute the 6 on the other side to make it 6 -32n. Since all you have to do is add, add -20n + 20 + 6 + -32n. Simplified the answer would be -12n + 26.
Hope that helps.
Serena, a 10th grade student.
Sure! I can help you with these questions. Let's solve them step by step.
1. To find the slope of the line given by the equation Y = x + 1, we can see that the equation is in the form of y = mx + b, where m represents the slope. In this case, the slope is the coefficient of x, which is 1. Therefore, the slope of the line is 1.
2. For the equation -6 + x/2 = 2, we need to isolate x. We can start by adding 6 to both sides of the equation to get rid of the -6:
-6 + 6 + x/2 = 2 + 6
x/2 = 8
To isolate x, we can multiply both sides of the equation by 2:
2 * (x/2) = 8 * 2
x = 16
So, the solution to the equation is x = 16.
3. To simplify the expression -4(5n - 5) + 6(1 - 7n), we can use the distributive property of multiplication over addition or subtraction.
-4(5n - 5) + 6(1 - 7n) = -20n + 20 + 6 - 42n
Now, we can combine like terms:
-20n + 20 + 6 - 42n = -62n + 26
So, the simplified expression is -62n + 26.
I hope this helps! Let me know if you have any further questions.