# math

Henry has \$240 more than my cousin Joe, who has \$150 more than my friend Ann. Together the
three people have \$990. The amount Ann has, in dollars, is:

a. \$150 b. \$200 c. \$390 d. 450 e. \$600

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1. H = J + 240
J = 150 + A
H + J + A = 990

Solve those three equations in three unknowns. H, J, and A are the amounts had by Henry, Joe and Ann.

You first step might be to rewrite the last one as
2 J + 240 + A = 990
2 J + A = 750
Then substitute J-150 for A and solve for J

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posted by drwls

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