The temperature of a 12.58g sample of calcium carbonate increases from 23.6degrees celcius to 38.2 degrees celcius. If the heat capacity is 0.82J/g-K, how many Joules of heat are absorbed
Looks to me like the temp change is 14.6K, so
.82J/gK * 12.58g * 14.6K = 150.6J
q=m*s*t
q=(12,58)*0.82*(38,2-23.6)
q=151 Joules
Well, well, well, looks like calcium carbonate is bringing the heat! Let's calculate the amount of heat absorbed, shall we?
First, let's find the change in temperature:
ΔT = final temperature - initial temperature
ΔT = 38.2°C - 23.6°C
ΔT = 14.6°C
Now, to calculate the heat absorbed:
q = m * C * ΔT
Where:
q is the heat absorbed (in Joules),
m is the mass of the sample (in grams),
C is the heat capacity (in J/g-K),
ΔT is the change in temperature (in °C).
Plugging in the values we've got:
q = 12.58g * 0.82J/g-K * 14.6°C
Now, I'll be your math sidekick and crunch those numbers for you:
q = 188.768J
So, the calcium carbonate sample absorbs approximately 188.768 Joules of heat. It's getting steamy in here!
To calculate the amount of heat absorbed, you can use the formula:
q = m * C * ΔT
where:
- q represents the amount of heat absorbed (in Joules),
- m is the mass of the sample (in grams),
- C is the heat capacity of the substance (in J/g-K),
- ΔT is the change in temperature (in degrees Celsius).
Given values:
m = 12.58 g
C = 0.82 J/g-K
ΔT = (final temperature) - (initial temperature) = 38.2°C - 23.6°C
Let's calculate the change in temperature first:
ΔT = 38.2°C - 23.6°C = 14.6°C
Now we can substitute the values into the formula:
q = 12.58 g * 0.82 J/g-K * 14.6°C
Calculating the result:
q = 162.0796 J
Therefore, approximately 162.08 Joules of heat are absorbed.
To calculate the amount of heat absorbed, we can use the equation:
Q = m * c * ΔT
Where:
Q represents the heat absorbed
m is the mass of the sample (in grams)
c is the specific heat capacity (in J/g-K)
ΔT is the change in temperature (in degrees Celsius)
Let's substitute the given values into the equation:
m = 12.58 g
c = 0.82 J/g-K
ΔT = 38.2°C - 23.6°C = 14.6°C
Now we can calculate Q:
Q = 12.58 g * 0.82 J/g-K * 14.6°C
First, let's convert the change in temperature from Celsius to Kelvin. To do this, we add 273.15 to the Celsius value:
14.6°C + 273.15 = 287.75 K
Now we can continue calculating Q:
Q = 12.58 g * 0.82 J/g-K * 287.75 K
Q ≈ 283.82 Joules
Therefore, approximately 283.82 Joules of heat are absorbed.