An object is dropped from a platform 100 feet high. Ignoring wind resistance, what will its speed be when it reaches the ground?
_____ ft/s
Please help me!!!
solution
height(h)= 100ft
since the object starts at rest,
initial speed(U)=0
Final speed (v)= ?
since the object is falling under the influence of gravity and downwards
a=g= 32.17 ft/s^2
so
we have
v2=u2+2gh
v2= 0+ 2*32.17*100
v2= 6434
v=80.21f/s
the final speed was 80.21 f/s
d=1/2gt^2
acceleration due to gravity= 32 ft/s^2
100= 1/2(32)t^2
100=16t^2
100/16 = 6.25
t^2= 6.25
t= 2.5
An object is dropped from a platform 100 feet high.ignoring wind resistance,how long will it take to reach the ground ?
Light travels approximately 982,080,000 ft/s, and one year has approximately 32,000,000 seconds. A light year is the distance light travels in one year.
State the speed in mi/s, using scientific notation. (1 mile = 5280 feet exactly, by definition; i.e., this is not a measurement.)
An object is thrown directly up (positive direction) with a velocity (vo) of 20.0 m/s and do= 0. How high does it rise (v = 0 cm/s at top of rise). Remember, acceleration is -9.80 m/s2.
To find the speed at which the object will hit the ground, you can use the following equation:
v^2 = u^2 + 2as
Where:
v = final velocity (which we want to find)
u = initial velocity (since the object is dropped from rest, the initial velocity = 0)
a = acceleration due to gravity (approximately 32 ft/s^2 near the surface of the Earth)
s = displacement or distance fallen (in this case, 100 ft)
Plugging in the given values:
v^2 = 0 + 2 * 32 * 100
v^2 = 6400
Taking the square root of both sides:
v = sqrt(6400)
v = 80 ft/s
Therefore, the object will hit the ground with a speed of 80 ft/s.