Which of these objects would reach 100 feet in the least amount of time? (1 point) Responses object C object C object B object B They would all reach 100 feet at the same time. They would all reach 100 feet at the same time. object A object A

It is not possible to answer this question without information about the objects and their respective speeds or velocities.

The temperature is dropping throughout the day as a cold front comes in. In City A, the temperature is changing by −5°F per hour, and in City B the temperature is changing by −3°F per hour. If the temperatures in both cities started at 70°F , which city is warmer, and what is the difference in their temperatures after 5 hours?(1 point) Responses City A is warmer by 2°F. City A is warmer by 2 degrees F . City B is warmer by 10°F. City B is warmer by 10 degrees F . City B is warmer by 2°F. City B is warmer by 2 degrees F . City A is warmer by 10°F.

After 5 hours, the temperature in City A would decrease by (−5°F/hour) * 5 hours = −25°F, resulting in a temperature of 70°F - 25°F = 45°F.

In City B, the temperature would decrease by (−3°F/hour) * 5 hours = −15°F, resulting in a temperature of 70°F - 15°F = 55°F.

Therefore, City B is warmer by 55°F - 45°F = 10°F.

So, the correct response is: City B is warmer by 10 degrees F.

To determine which object would reach 100 feet in the least amount of time, we need more information about the objects. Since the response options are repeated, it seems that the information provided is incomplete.

To find the object that would reach 100 feet in the least amount of time, we typically need to know the rate at which each object travels. The equation for calculating time is:

Time = Distance / Speed

If we have the speed for each object, we can determine the time it would take for them to reach 100 feet by dividing the distance (100 feet) by their respective speeds. The object with the smallest resulting time value would reach the distance in the least amount of time.

Given the information you've provided, it is not possible to determine the object that would reach 100 feet in the least amount of time.