An object is dropped from a platform 100 feet high. Ignoring wind resistance, what will its speed be when it reaches the ground?
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To find the speed of an object when it reaches the ground, we can use the laws of motion and the concept of free fall. The speed will depend on the height from which the object is dropped.
The equation that describes the motion of a falling object is given by:
v² = u² + 2as
Where:
- v represents the final velocity (speed) of the object when it reaches the ground.
- u is the initial velocity, which is 0 in this case because the object is dropped from rest.
- a is the acceleration due to gravity, which is approximately 32.2 ft/s².
- s represents the vertical distance the object falls.
In this case, the vertical distance or height is 100 feet, so we can substitute the values into the equation:
v² = 0² + 2 * 32.2 * 100
Simplifying the equation:
v² = 2 * 32.2 * 100
v² = 6440
Taking the square root of both sides of the equation:
v = √6440
v ≈ 80.25 ft/s
Therefore, when the object reaches the ground, its speed will be approximately 80.25 ft/s.