physics

Sam tosses a ball horizontally off a footbridge at 4.8 m/s. How much time passes after he releases it until its speed doubles?

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asked by Anonymous
  1. When the speed has doubled, the vertical component of speed will be
    sqrt[(9.6)^2 - (4.8)^2] = 8.31 m/s
    (The horizontal velocity component will remain 4.8 m/s.)

    The time needed to attain that vertical velocity component is
    t = (8.31 m/s)/g = 0.848 seconds

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    posted by drwls

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