This is a 8th grade question:
Given C+C=D, D+E=17, A+2C=D, and 2B+C=8, what is the value of A+B+C+D???
Can you also show how you got it?
To start, if C+C=D and A+2C = D, then A = 0.
With E and B being only in one equation each, I can't figure out how to solve for B, C or D. Do you have any typos?
Eq1 and 3. 2C=D,A=0. Eq2 and 4.C=O,B=4,D=0,E=17.Therefore A+B+C+D=21
To find the value of A+B+C+D, we need to solve the set of equations given.
We have the equations:
1) C + C = D
2) D + E = 17
3) A + 2C = D
4) 2B + C = 8
Let's solve these equations step by step:
First, let's rewrite equation 1) in a simpler form:
2C = D
Now let's substitute this value of D in equations 2) and 3):
2C + E = 17 (substituting D in equation 2)
A + 2C = 2C (substituting D in equation 3)
Now let's simplify equation 3):
A + 2C = 2C
A = 0
We have found the value of A, which is 0.
Substituting A = 0 back in equation 3):
0 + 2C = 2C
2C = 2C
This equation shows that C can have any value. It is an indeterminate variable.
Now let's substitute D = 2C in equation 2):
2C + E = 17
We can rewrite this equation as:
E = 17 - 2C
Finally, we substitute D = 2C in equation 4):
2B + C = 8
We can rewrite this equation as:
2B = 8 - C
Now let's sum up all the variables we need to find (A+B+C+D):
A + B + C + D = 0 + B + C + 2C
Simplifying this equation:
A + B + C + D = B + 3C
We have found that A + B + C + D is equivalent to B + 3C.
Therefore, we still need one more piece of information to solve for A + B + C + D, as it depends on the values of B and C.