f(x)=x^3+3x find the rate of change between the two stated values x:1 to 2
The rate of change is the derivative,
f'(x) = 3x^2 + 3.
Between x = 1 and 2, it increases from 6 to 15
http://www.answers.com/college
http://www.answers.com/collage
http://www.shapecollage.com/
Interesting!
To find the rate of change between two values of a function, we need to compute the difference in the function values at those points and divide it by the difference in the x-values.
First, let's find the values of the function at x=1 and x=2:
For x = 1:
f(1) = (1)^3 + 3(1) = 1 + 3 = 4
For x = 2:
f(2) = (2)^3 + 3(2) = 8 + 6 = 14
Now, we have f(1) = 4 and f(2) = 14. The rate of change between these two points is given by:
Rate of change = (f(2) - f(1)) / (2 - 1)
= (14 - 4) / (2 - 1)
= 10 / 1
= 10
Therefore, the rate of change between the two values x: 1 and 2 is 10.