A 1502.7 kg car is traveling at 33.1 m/s
when the driver takes his foot off the gas
pedal. It takes 4.7 s for the car to slow down
to 20 m/s.
How large is the net force slowing the car?
Answer in units of N
Vf=Vi + at find a
then, force=mass*a
To find the net force slowing down the car, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration. In this case, the acceleration is the change in velocity over time.
The change in velocity of the car is given by the initial velocity minus the final velocity. Therefore, the change in velocity is 33.1 m/s - 20 m/s = 13.1 m/s.
The acceleration of the car can be calculated using the formula:
acceleration = change in velocity / time
Substituting the given values, we get:
acceleration = 13.1 m/s / 4.7 s = 2.787 m/s^2
Now, we can calculate the net force using the formula:
net force = mass × acceleration
Substituting the given mass and calculated acceleration, we get:
net force = 1502.7 kg × 2.787 m/s^2
Calculating the product, we find the net force:
net force ≈ 4186.5 N
Therefore, the net force slowing the car is approximately 4186.5 Newtons.