if a membrane filter from a cigarette weighs 0.0313g bfore sample has been drawn through and 0.0548g after what is the weight of particluate matter on filter in g and mg/cigarette ?
Volume of air ed through=32x50ml=?mL=?L
concentration of particulate matter=?mg/L =? mg/m3 please?

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  1. I will be happy to check your calcuations. It seems straightforward.

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  2. weight of particluate on filter 0.0235g = 23mg/cigarette
    volume of air ed through 32x50ml=
    1600ml =1.6 l
    I cant figure how to do this
    concentration of particulate matter=
    ?mg/l = ? mg/m3
    help appreciated

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