If a sample of Mg3(PO4)2, has a mass of 0.600 g, what is the mass of phosphorus in that sample?
To determine the mass of phosphorus (P) in the sample of Mg3(PO4)2, we need to find the molar mass of Mg3(PO4)2 and then calculate the mass of phosphorus.
1. Begin by finding the molar mass of Mg3(PO4)2 by adding up the atomic masses of all the elements in the compound.
- The atomic mass of Mg (magnesium) is approximately 24.31 g/mol.
- The atomic mass of P (phosphorus) is approximately 30.97 g/mol.
- The atomic mass of O (oxygen) is approximately 16.00 g/mol.
2. Since there are three magnesium atoms in the formula, the molar mass of Mg3(PO4)2 can be calculated as follows:
Mg3(PO4)2 = (3 * Mg) + (2 * P) + (8 * O)
= (3 * 24.31 g/mol) + (2 * 30.97 g/mol) + (8 * 16.00 g/mol)
= 72.93 g/mol + 61.94 g/mol + 128.00 g/mol
= 262.87 g/mol
3. Now, we know that the molar mass of Mg3(PO4)2 is 262.87 g/mol.
4. To find the mass of phosphorus in the sample, we can use the following formula:
Mass of P = (Mass of Mg3(PO4)2 * Number of moles of P) / Molar mass of Mg3(PO4)2
5. We are given that the sample has a mass of 0.600 g.
6. To calculate the number of moles of phosphorus, we need to divide the molar mass of P (30.97 g/mol) by the molar mass of Mg3(PO4)2 (262.87 g/mol).
Number of moles of P = Mass of P / Molar mass of P
= 0.600 g / 262.87 g/mol
≈ 0.002284 mol
7. Finally, substitute the values into the formula:
Mass of P = (0.600 g * 0.002284 mol) / 1 mol
≈ 0.001370 g
Therefore, the mass of phosphorus in the given sample of Mg3(PO4)2 is approximately 0.001370 g.
To determine the mass of phosphorus in the sample of Mg3(PO4)2, we need to calculate the molar mass of Mg3(PO4)2 and find the mass of phosphorus relative to the compound's formula.
Here are the steps to calculate the mass of phosphorus:
Step 1: Determine the molar mass of Mg3(PO4)2:
- The molar mass of magnesium (Mg) is 24.31 g/mol.
- The molar mass of phosphorus (P) is 30.97 g/mol.
- The molar mass of oxygen (O) is 16.00 g/mol.
- The molar mass of the phosphate group (PO4) is (1 * P) + (4 * O) = (1 * 30.97) + (4 * 16.00) = 94.97 g/mol.
- The molar mass of Mg3(PO4)2 is (3 * Mg) + (2 * PO4) = (3 * 24.31) + (2 * 94.97) = 262.57 g/mol.
Step 2: Calculate the mass of phosphorus:
- Divide the molar mass of phosphorus by the molar mass of Mg3(PO4)2: (1 * 30.97) / 262.57 = 0.1179.
- Multiply the result by the mass of the given sample: 0.1179 * 0.600 g = 0.0707 g.
Therefore, the mass of phosphorus in the sample of Mg3(PO4)2 is approximately 0.0707 grams.
mols Mg3(PO4)2 = grams/molar mass
mols P atoms is 2x that.
mass P atoms = mols x atomic mass.
It can be done another way by find the percent P in Mg3(PO4)2.
%P = (2*atomic mass P)/(molar mass Mg3(PO4)2)*100 = ?
Then 0.600 x %P/100 = ?