1.4 Orthophosphate (PO4) is determined by weighing as ammonium phosphomolybdate. (NHA)PO4.12M003. Calculate the percent P in the sample and percent P₂Os if 1.1682 g precipitate were obtained from a 0.2711 g sample.

Question

DrBob222 · Answer

You have the wrong formula for ammonium dodecaphophomolybdate. it should be (NH4​)3​[P(Mo3​O10​)4​] or you could have written (NH4)3P.12MoO3 The molar mass of this canary yellow ppt is 1876.58 g/mol. %P in sample = mass ppt*(molar mass P/molar mass (NH4​)3​[P(Mo3​O10​)4​])/mass sample*100 = 1.1682(30.97/1876.58)/0.2711*100 = % P. Check the substitutions to make sure I didn't make a typo. If you want %P2O5 then multiply what you get for %P x (molar mass P2O5/2P) = ? Post your work if you get stuck.

Step-by-Step Bot · Answer

To determine the percent P in the sample and percent P₂O₅, we need to follow these steps: Step 1: Calculate the moles of (NH₄)₃PO₄.12 MoO₃ precipitate using its molar mass. 1. Find the molar mass of (NH₄)₃PO₄.12MoO₃: - Mass of (NH₄)₃PO₄ = 3(N) + 12(H) + (P) + 4(4O) = 3(14.01) + 12(1.01) + 1(31.00) + 4(16.00) = 149.06 g/mol - Mass of MoO₃ = 12(Mo) + 3(16.OO) = 12(95.95) + 3(16.00) = 272.O9 g/mol Therefore, the molar mass of (NH₄)₃PO₄.12MoO₃ is: Mass of (NH₄)₃PO₄.12MoO₃ = 149.06 + 272.09 = 421.15 g/mol 2. Calculate the number of moles of (NH₄)₃PO₄.12MoO₃ precipitate: Moles = Mass / Molar mass = 1.1682 g / 421.15 g/mol Step 2: Calculate the moles of P in the sample using stoichiometry. 1. Based on the balanced equation, the molar ratio between (NH₄)₃PO₄ and P is 1:1. This means that the number of moles of (NH₄)₃PO₄.12MoO₃ is equal to the number of moles of P. 2. The moles of P in the sample is therefore equal to the moles of (NH₄)₃PO₄.12MoO₃ calculated in step 1. Step 3: Calculate the percent P in the sample. 1. Calculate the mass of P in the sample: Mass of P = Moles of P x Molar mass of P = Moles of (NH₄)₃PO₄.12MoO₃ x Molar mass of P 2. Calculate the percent P in the sample: Percent P = (Mass of P / Mass of the sample) x 100 Step 4: Calculate the percent P₂O₅ in the sample. 1. Based on the balanced equation, the molar ratio between P and P₂O₅ is 1:2. This means that the moles of P₂O₅ is twice the moles of P. 2. Calculate the moles of P₂O₅: Moles of P₂O₅ = 2 x Moles of P 3. Calculate the mass of P₂O₅: Mass of P₂O₅ = Moles of P₂O₅ x Molar mass of P₂O₅ 4. Calculate the percent P₂O₅ in the sample: Percent P₂O₅ = (Mass of P₂O₅ / Mass of the sample) x 100 Now let's calculate the values step by step: Step 1: Molar mass of (NH₄)₃PO₄.12MoO₃ = 421.15 g/mol Moles of (NH₄)₃PO₄.12MoO₃ = 1.1682 g / 421.15 g/mol Step 2: Moles of P = Moles of (NH₄)₃PO₄.12MoO₃ Step 3: Mass of P = Moles of P x Molar mass of P Percent P = (Mass of P / Mass of the sample) x 100 Step 4: Moles of P₂O₅ = 2 x Moles of P Mass of P₂O₅ = Moles of P₂O₅ x Molar mass of P₂O₅ Percent P₂O₅ = (Mass of P₂O₅ / Mass of the sample) x 100 Now you can substitute the values into the formulas to get the final answers.

Explain Bot · Answer

To calculate the percent P in the sample and percent P₂O₅, we need to follow a step-by-step process. Step 1: Calculate the molar mass of the precipitate The precipitate has the formula (NH₄)₃PO₄·12MoO₃. To calculate its molar mass, we need to sum the molar masses of all the atoms present in the formula. The molar masses of each element are as follows: - N (Nitrogen): 14.01 g/mol - H (Hydrogen): 1.01 g/mol - O (Oxygen): 16.00 g/mol - P (Phosphorus): 31.00 g/mol - Mo (Molybdenum): 95.94 g/mol Now, using the formula, we calculate the molar mass of the precipitate: (3 x (14.01 + 1.01)) + (1 x 31.00) + (12 x (16.00 + (3 x 16.00))) + (3 x 95.94) = 1327.54 g/mol Step 2: Calculate the moles of the precipitate To calculate the moles of the precipitate, divide the mass of the precipitate by its molar mass: moles of precipitate = mass of precipitate / molar mass of precipitate moles of precipitate = 1.1682 g / 1327.54 g/mol moles of precipitate = 0.000881 mol Step 3: Calculate the moles of P in the sample From the balanced chemical equation, we know that 1 mol of (NH₄)₃PO₄ contains 1 mole of P. Therefore, the moles of P in the sample are the same as the moles of the precipitate: moles of P = 0.000881 mol Step 4: Calculate the mass of the sample Given that the mass of the sample is 0.2711 g, we already have this value. Step 5: Calculate the percent P in the sample The percent P in the sample is obtained by dividing the moles of P by the mass of the sample, and then multiplying by 100: percent P in the sample = (moles of P / mass of sample) x 100 percent P in the sample = (0.000881 mol / 0.2711 g) x 100 Step 6: Calculate the percent P₂O₅ To calculate the percent P₂O₅, we need to consider the molar mass ratio between P and P₂O₅. From the chemical formula, we see that 1 mol of P corresponds to 2 mol of P₂O₅. So the moles of P₂O₅ can be calculated as follows: moles of P₂O₅ = 2 x moles of P Finally, we can calculate the percent P₂O₅: percent P₂O₅ = (moles of P₂O₅ / mass of sample) x 100 percent P₂O₅ = (2 x 0.000881 mol / 0.2711 g) x 100 By following these steps, you can calculate both the percent P in the sample and percent P₂O₅.

1.4 Orthophosphate (PO4) is determined by weighing as ammonium phosphomolybdate. (NHA)PO4.12M003. Calculate the percent P in the sample and percent P₂Os if 1.1682 g precipitate were obtained from a 0.2711 g sample.

You have the wrong formula for ammonium dodecaphophomolybdate. it should be (NH4​)3​[P(Mo3​O10​)4​] or you could have written (NH4)3P.12MoO3 The molar mass of this canary yellow ppt is 1876.58 g/mol.

To determine the percent P in the sample and percent P₂O₅, we need to follow these steps:

To calculate the percent P in the sample and percent P₂O₅, we need to follow a step-by-step process.

You have the wrong formula for ammonium dodecaphophomolybdate. it should be (NH4)3[P(Mo3O10)4] or you could have written (NH4)3P.12MoO3 The molar mass of this canary yellow ppt is 1876.58 g/mol.