a car of mass 3000kg moving at 20m/s is suddenly brought to a stop when a deer crosses the road. if a braking force of 300,000 is needed to bring the car to a stop, what was the duration of the force?
force*brakingtime=mass*changevelocity
solve for braking time.
a car of mass 1200 kg accelerates steadily from rest down an steady incline at 15 degree to the horizontal . if the slope is 100 m long , calculate the work out the loss potential energy as the car moves down the slope
To find the duration of the force needed to bring the car to a stop, we can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration.
In this case, the car is brought to a stop, so its final velocity is 0 m/s. The initial velocity is given as 20 m/s, and the mass of the car is 3000 kg.
Using the equation:
Force = Mass x Acceleration
We can rearrange the equation to solve for acceleration:
Acceleration = Force / Mass
Plugging in the values:
Acceleration = 300,000 N / 3000 kg
Acceleration = 100 m/s^2
Now we have the acceleration, and we know the final velocity is 0 m/s. We can use another equation of motion to find the time it takes for the car to stop:
Final Velocity = Initial Velocity + (Acceleration x Time)
0 m/s = 20 m/s + (100 m/s^2 x Time)
Rearranging the equation to solve for time:
Time = (0 m/s - 20 m/s) / (100 m/s^2)
Time = -20 m/s / 100 m/s^2
Time = -0.2 s
Therefore, the duration of the force needed to bring the car to a stop is 0.2 seconds.