A car mass 600kg moving a speed 20m/s.it collides with a stationary car mass 900kg.if the first car bounce back 4m/s.what speed does the second object after collision
conserve momentum
600*20 + 900*0 = 600(-4) + 900v
Increase grade
Good
Well, you know what they say in the world of car collisions: "It's all about that back bounce!" Now, let's crunch some numbers while having a barrel of laughs!
First off, let's calculate the momentum of the first car before the collision. Momentum (p) is calculated by multiplying mass (m) by velocity (v). So, the momentum of the first car is:
p1 = m1 * v1
= 600 kg * 20 m/s
= 12,000 kg·m/s
Now, taking into account the conservation of momentum (which, by the way, is quite mysterious and magical), we can say that the total momentum before the collision equals the total momentum after the collision.
Total momentum before = Total momentum after
In this case, the second car is stationary before the collision, so its initial momentum is zero (since v2 = 0 m/s). Therefore, we can rewrite our equation as:
p1 = p1' + p2'
Where p1' is the momentum of the first car after bouncing back, and p2' is the momentum of the second car after the collision.
Now we can calculate the momentum of the first car after the collision:
p1' = m1 * v1'
12,000 kg·m/s = 600 kg * (-4 m/s)
v1' = -8000 kg·m/s
And finally, solving for the momentum of the second car after the collision:
p2' = p1 - p1'
p2' = 12,000 kg·m/s - (-8000 kg·m/s)
p2' = 20,000 kg·m/s
Now, we can find the velocity (v2') of the second car after the collision by dividing its momentum by its mass:
v2' = p2' / m2
= 20,000 kg·m/s / 900 kg
≈ 22.22 m/s
So, after crunching some numbers and clowning around, we find that the second car will have a velocity of approximately 22.22 m/s after the collision.
Just remember, though, that in real-life situations, other factors like friction and deformation play a role. So, don't go bouncing around expecting these numbers to hold up perfectly. Drive safely, my friend!
To find the speed of the second car after the collision, we can use the principle of conservation of momentum. According to this principle, the total momentum before the collision is equal to the total momentum after the collision.
The momentum of an object is defined as the product of its mass and velocity. So, we can calculate the momentum of each car before the collision.
Momentum of the first car before the collision:
Initial momentum = mass × velocity
= 600 kg × 20 m/s
= 12,000 kg·m/s
The second car is stationary, so its initial momentum is zero.
After the collision, the first car bounces back with a velocity of 4 m/s. This means the velocity is negative since it is in the opposite direction to its initial motion.
Now, let's represent the final velocity of the second car as "v2".
Applying the conservation of momentum, the total momentum before the collision equals the total momentum after the collision.
Total initial momentum = Total final momentum
(Initial momentum of first car) + (Initial momentum of second car) = (Final momentum of first car) + (Final momentum of second car)
(12,000 kg·m/s) + (0 kg·m/s) = (600 kg × (-4 m/s)) + (900 kg × v2)
12,000 kg·m/s = (-2,400 kg·m/s) + (900 kg × v2)
Now, we can solve for "v2" by rearranging the equation:
12,000 kg·m/s + 2,400 kg·m/s = 900 kg × v2
14,400 kg·m/s = 900 kg × v2
Divide both sides of the equation by 900 kg:
v2 = 14,400 kg·m/s ÷ 900 kg
v2 = 16 m/s
Therefore, the speed of the second car after the collision is 16 m/s.