A reguluation racquetball court should have a perimeter of 120 ft, with a length that is twice the width find the length and the width of a court
W = Width
L = Length
P = Perimeter
L = 2 W
P = 2 L + 2 W = 120 ft
2 * 2 W + 2 W = 120
4 W + 2 W = 120
6 W = 120 Divide both sides by 6
W = 120 / 6
W = 20 ft
L = 2 W
L = 2 * 20
L = 40 ft
To find the length and width of the racquetball court, we can set up a system of equations based on the given information.
Let's assume the width of the court is represented by "w" (in feet).
According to the given information, the length of the court is twice the width. So, the length is 2w.
The perimeter of a rectangle is given by the formula: P = 2w + 2l, where P is the perimeter, w is the width, and l is the length.
We are given that the perimeter of the court is 120 ft:
120 = 2w + 2(2w)
Simplifying the equation:
120 = 2w + 4w
120 = 6w
Dividing both sides of the equation by 6, we get:
w = 20
Now that we have the value of w, we can substitute it back into the equation to find the length:
l = 2w
l = 2(20)
l = 40
So, the width of the court is 20 ft, and the length of the court is 40 ft.