Consider the 671 N weight held by two cables
shown below. The left-hand cable had ten-
sion T2 and makes an angle of 47� with the
ceiling. The right-hand cable had tension T1
and makes an angle of 43� with the ceiling.
a) What is the tension in the cable labeled
T1 slanted at an angle of 43�?
Answer in units of N
b) What is the tension in the cable labeled T2
slanted at an angle of 47�?
Answer in units of N
well,the horizontal components left and right are equal an opposite, and the vertical components add to 671N.
Horizontal
T1*cos47+T2*cos43=0
Vertical
T1*Sin47+T2*sin43=671
two equations, two unknowns, solve it.
How do you solve for them though? That's what Im stuck on
I know that but I just don't get it
T1 = 1.1 ??
T2 = 719.6 ??
t1cos47 + t2cos43 = 0
t1cos47 = t2cos43
t1 = 1.1
t1sin47 + t2sin43 = 671
t2sin43 = 490.7
t2 = 719.6
I really have no idea how to do this
why don't you compute the sin, cos of those angles, and make them coefficents of the tension t1, t2?
t1cos47 = t2cos43
t1=1.1 T2
PUt that into the second equation for t1, then solve for t2
1.1sin47 + t2sin43 = 671
.804 + t2sin43 = 671
t2sin43 = 670.196
t2 = 982.694
Im really getting frustrated with this and its due at 11 pm tonight. Please help me. Is t1 right though??
Nothing is "shown below."
Perform vertical and horizontal force balances and solve for the two unknowns, T1 and T2.
Show your work for further assistance.
Those answer are obviously wrong. The tension will not be equal, but close, the angles are very close.
Show me your work.