can someone check my answer
Graph by first solving for y.
x + 2y = 8
x-x+2y=8-x
2y=8-x
2y/2=8/2-x
y=4-x
y=4-x/2
y=4-1/2x
I am having some trouble following this since I see nothing.
x+2y=8
x-x+2y=8-x
2y=8-x
2y/2=8/2-x
y=4-x
y=4-x/2
y=4-1/2x
x+2y=8
x-x+2y=8-x
2y=8-x
2y/2=8/2-x WHOA! divide that x by 2 as well!!
y=4-x
y=4-x/2 Yes, here you caught up but the 2 lines above are wrong because should be x/2
y=4-1/2x
To check your answer, you need to substitute the value of y that you found back into the original equation and see if both sides of the equation are equal.
Let's substitute y = 4 - (1/2)x back into the equation x + 2y = 8:
x + 2(4 - (1/2)x) = 8
Simplifying:
x + 8 - x = 8 - x/2
The x terms cancel out:
8 = 8 - (1/2)x
Now, let's solve for x:
8 + (1/2)x = 8
Subtract 8 from both sides:
(1/2)x = 0
Multiply both sides by 2 to clear the fraction:
x = 0
Now that we have x = 0, we can substitute it back into y = 4 - (1/2)x to find the value of y:
y = 4 - (1/2)(0)
y = 4
So the solution to the equation x + 2y = 8 when you solve for y and substitute it back is x = 0 and y = 4.