Leo has 8 more markers than colored pencils. He has a total of 32 markers and colored pencils. How many of each kind does he have?
Let x = colored pencils.
x + x + 8 = 32
2x = 32 - 8
2x = 24
x = 12
To find the number of markers and colored pencils Leo has, we can set up a system of equations.
Let's assume the number of colored pencils is x.
According to the problem, Leo has 8 more markers than colored pencils. So, the number of markers is x + 8.
The total number of markers and colored pencils is given as 32.
So, our first equation is: x + (x + 8) = 32
Simplifying the equation, we have: 2x + 8 = 32
Next, we can solve for x.
Subtracting 8 from both sides of the equation yields: 2x = 24
Dividing both sides by 2 gives: x = 12
Therefore, Leo has 12 colored pencils (x) and the number of markers can be found by adding 8 to the number of colored pencils: 12 + 8 = 20
So, Leo has 12 colored pencils and 20 markers.