Consider the reaction between sodium metal and chlorine gas to form sodium chloride (table salt).

2Na(s) + Cl2(g) 2NaCl(s)
If 3.6 moles of chlorine react with sufficient sodium, how many grams of sodium chloride will be formed?

3.6mol Cl₂ x 2mol NaCl x 58.44g NaCl = 420.78

It appears for each mole of chlorine, you get twice that number of moles of sodium chloride.

What is the mass of 7.2moles of NaCl?

To find the number of grams of sodium chloride formed, we need to use the stoichiometry of the reaction.

The balanced equation tells us that 2 moles of Na react with 1 mole of Cl2 to form 2 moles of NaCl.

From the balanced equation, we can set up the following stoichiometric conversion:

3.6 moles Cl2 * (2 moles NaCl / 1 mole Cl2) * (58.44 g NaCl / 1 mole NaCl) = ?

Let's calculate it step-by-step:

Step 1: Convert moles of Cl2 to moles of NaCl.
3.6 moles Cl2 * (2 moles NaCl / 1 mole Cl2) = 7.2 moles NaCl

Step 2: Convert moles of NaCl to grams of NaCl.
7.2 moles NaCl * (58.44 g NaCl / 1 mole NaCl) = 420.768 g NaCl

Therefore, when 3.6 moles of chlorine react with sufficient sodium, 420.768 grams of sodium chloride will be formed.

To calculate the number of grams of sodium chloride formed, we need to use the given number of moles of chlorine and the stoichiometry of the reaction.

Step 1: Determine the molar mass of sodium chloride (NaCl).
The molar mass of sodium (Na) is 22.99 g/mol, and the molar mass of chlorine (Cl) is 35.45 g/mol. Adding them together, we get:
NaCl = 22.99 g/mol + 35.45 g/mol = 58.44 g/mol.

Step 2: Calculate the number of moles of sodium chloride formed.
According to the stoichiometry of the balanced chemical equation, 1 mole of Cl2 reacts with 2 moles of NaCl. So, the number of moles of NaCl formed can be calculated as follows:
Number of moles of NaCl = (3.6 mol Cl2) x (2 mol NaCl / 1 mol Cl2) = 7.2 mol NaCl.

Step 3: Convert moles to grams.
To convert moles to grams, we use the molar mass of NaCl determined in Step 1.
Mass of NaCl = (Number of moles of NaCl) x (Molar mass of NaCl)
Mass of NaCl = (7.2 mol) x (58.44 g/mol)
Mass of NaCl = 420 g.

Therefore, 3.6 moles of chlorine will react to form 420 grams of sodium chloride.