Sodium reacts with chlorine to form the compound sodium chloride, or salt. The chemical formula below shows how the two elements combine into a compound.
2Na + Cl2 → 2NaCl
If the total mass of the reactants is 58.44 amu, what will be the total mass of the products?
60 amu
60 amu
116.88 amu
116.88 amu
58.44 amu
58.44 amu
29.22 amu
The total mass of the products can be calculated by finding the sum of the atomic masses of sodium chloride (NaCl).
The atomic mass of sodium (Na) is 23 amu, and the atomic mass of chlorine (Cl) is 35.5 amu.
So, the atomic mass of NaCl is 23 + 35.5 = 58.5 amu.
Since 2 moles of Na react with 1 mole of Cl2 to form 2 moles of NaCl, the molecular mass of NaCl is 2 * 58.5 = 117 amu.
Therefore, the total mass of the products will be 116.88 amu.
The chemical equation for the reaction between sodium and chlorine is:
2Na + Cl2 → 2NaCl
From the equation, we can see that for every 2 moles of sodium (Na), we need 1 mole of chlorine (Cl2) to form 2 moles of sodium chloride (NaCl).
To find the mass of the products, we need to calculate the total mass of sodium chloride.
The atomic mass of sodium (Na) is 22.99 amu and the atomic mass of chlorine (Cl) is 35.45 amu. Adding them together, we get:
22.99 amu + 35.45 amu = 58.44 amu
So, the total mass of the products, sodium chloride, will also be 58.44 amu. Therefore, the correct answer is:
58.44 amu
To find the total mass of the products, you can calculate the molar mass of the reactants and then convert it to the products.
In the given chemical equation, the reactants are sodium (Na) and chlorine (Cl2), and the product is sodium chloride (NaCl).
To calculate the molar mass of the reactants:
- The atomic mass of sodium (Na) is approximately 22.99 amu
- The atomic mass of chlorine (Cl) is approximately 35.45 amu
- Since the coefficient for chlorine is 2, we need to multiply its atomic mass by 2, which gives us 2 * 35.45 amu = 70.90 amu
Now, we add the molar masses of sodium and chlorine to get the total molar mass of the reactants:
22.99 amu + 70.90 amu = 93.89 amu
Since the total mass of the reactants is given as 58.44 amu, we can set up a proportion to find the mass of the products:
(58.44 amu) / (93.89 amu) = (x amu) / (total mass of the products)
Solving for x, we have:
x = (58.44 amu * total mass of the products) / 93.89 amu
Therefore, the total mass of the products would be calculated as follows:
x = (58.44 amu * 116.88 amu) / 93.89 amu = 72.86 amu
So, the correct answer is 72.86 amu.