3) You make a solution by dissolving 3.4g Ba(OH)2 in enough water to make 450ml of salt solution.
a. What is the molarity of the solution?
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To find the molarity of the solution, you need to know the number of moles of Ba(OH)2 and the total volume in liters.
First, you need to calculate the number of moles of Ba(OH)2. This can be done by dividing the given mass by the molar mass of Ba(OH)2.
To find the molar mass of Ba(OH)2, you need to look up the atomic masses of barium (Ba), oxygen (O), and hydrogen (H) from the periodic table.
The atomic mass of barium (Ba) is 137.33 g/mol.
The atomic mass of oxygen (O) is 16.00 g/mol.
The atomic mass of hydrogen (H) is 1.01 g/mol.
Now, let's calculate the molar mass of Ba(OH)2:
Ba: 1 Ba x 137.33 g/mol = 137.33 g/mol
O: 2 O x 16.00 g/mol = 32.00 g/mol
H: 2 H x 1.01 g/mol = 2.02 g/mol
Total molar mass of Ba(OH)2:
137.33 g/mol + 32.00 g/mol + 2.02 g/mol = 171.35 g/mol
Now, let's calculate the number of moles of Ba(OH)2:
Number of moles = Mass / Molar mass
Number of moles = 3.4 g / 171.35 g/mol
Now that you have the number of moles, you can calculate the molarity. Molarity is defined as moles of solute divided by the volume of solution in liters.
To find the volume in liters, you need to convert the given volume from milliliters to liters:
450 mL = 450 / 1000 L = 0.45 L
Now, let's calculate the molarity using the formula:
Molarity (M) = moles of solute / volume of solution (in liters)
Molarity (M) = (3.4 g / 171.35 g/mol) / 0.45 L
By plugging in the values and performing the calculation, you can find the molarity of the solution.