How do I calculate the amount of heat needed to convert 96g of ice at -24 degrees celciua to water at 28 degrees celciua?
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To calculate the amount of heat needed to convert ice to water at different temperatures, you can use the following steps:
1. Calculate the heat required to raise the temperature of the ice from -24°C to 0°C.
2. Calculate the heat required to melt the ice at 0°C.
3. Calculate the heat required to raise the temperature of the water from 0°C to 28°C.
4. Add up the results from steps 1 to 3 to find the total heat needed.
Here's the step-by-step calculation:
Step 1: Calculate the heat required to raise the temperature of ice from -24°C to 0°C.
q1 = mass × specific heat capacity × temperature change
q1 = 96g × 2.09 J/g°C × (0°C - (-24°C))
q1 = 96g × 2.09 J/g°C × 24°C
Step 2: Calculate the heat required to melt the ice at 0°C.
q2 = mass × heat of fusion
q2 = 96g × 334 J/g
Step 3: Calculate the heat required to raise the temperature of water from 0°C to 28°C.
q3 = mass × specific heat capacity × temperature change
q3 = 96g × 4.18 J/g°C × (28°C - 0°C)
q3 = 96g × 4.18 J/g°C × 28°C
Step 4: Calculate the total heat required.
total heat = q1 + q2 + q3
Simply substitute the known values into the equations and perform the calculations to find the total heat.
To calculate the amount of heat needed to convert ice at -24 degrees Celsius to water at 28 degrees Celsius, you can follow these steps:
1. Determine the heat required to raise the temperature of ice from -24 degrees Celsius to 0 degrees Celsius.
2. Calculate the heat required to convert the ice at 0 degrees Celsius to water at 0 degrees Celsius.
3. Find the heat needed to raise the temperature of the water from 0 degrees Celsius to 28 degrees Celsius.
4. Add up the three steps to obtain the total heat required.
Now let's calculate each step:
Step 1: Determining the heat required to raise the temperature of ice from -24 degrees Celsius to 0 degrees Celsius.
The specific heat capacity of ice is 2.09 J/g°C. To calculate the heat, use the formula:
Q1 = mass × specific heat capacity × change in temperature
Q1= 96g × 2.09 J/g°C × (0 - (-24)°C)
Step 2: Calculating the heat required to convert the ice at 0 degrees Celsius to water at 0 degrees Celsius.
The heat of fusion (also known as the latent heat) required to convert ice at 0 degrees Celsius to water at 0 degrees Celsius is 334 J/g.
Q2 = mass × heat of fusion
Q2 = 96g × 334 J/g
Step 3: Finding the heat needed to raise the temperature of the water from 0 degrees Celsius to 28 degrees Celsius.
The specific heat capacity of water is 4.18 J/g°C. Use the formula:
Q3 = mass × specific heat capacity × change in temperature
Q3 = 96g × 4.18 J/g°C × (28 - 0)°C
Step 4: Calculating the total heat required.
Total heat required = Q1 + Q2 + Q3
Now you can simply add up the values of Q1, Q2, and Q3 to find the total heat required.