Find Molecular and net ionic equation for
Al(NO3)3 + Na2CO3
To find the molecular and net ionic equations for the reaction between Al(NO3)3 (aluminum nitrate) and Na2CO3 (sodium carbonate), we need to identify and balance the chemical equation.
The compound aluminum nitrate (Al(NO3)3) dissociates into its respective ions in water, forming aluminum cations (Al³⁺) and nitrate anions (NO3⁻):
Al(NO3)3(s) → Al³⁺(aq) + 3 NO3⁻(aq)
Similarly, sodium carbonate (Na2CO3) dissociates into its respective ions in water, forming sodium cations (Na⁺) and carbonate anions (CO3²⁻):
Na2CO3(aq) → 2 Na⁺(aq) + CO3²⁻(aq)
Now, let's combine the balanced chemical equations for both reactants:
Al(NO3)3(s) + Na2CO3(aq) → Al³⁺(aq) + 3 NO3⁻(aq) + 2 Na⁺(aq) + CO3²⁻(aq)
To write the molecular equation, we represent the reactants and products exactly as they are:
Al(NO3)3(s) + Na2CO3(aq) → Al(NO3)3(aq) + Na2CO3(aq)
For the net ionic equation, we eliminate the spectator ions (ions that appear on both sides of the equation) to focus on the actual substances involved in the chemical change. In this case, the spectator ions are NO3⁻ and Na⁺. We only consider the ions that undergo a change:
Al³⁺(aq) + CO3²⁻(aq) → Al(NO3)3(aq) + Na2CO3(aq)
So, the net ionic equation for the reaction between Al(NO3)3 and Na2CO3 is:
Al³⁺(aq) + 3 CO3²⁻(aq) → Al(NO3)3(aq) + Na2CO3(aq)