What is the total iconic equation and net ionic equation of the reaction between barium nitrate and ammonium oxalate Ba(NO3)2 + (NH4)2C2O4 → Ba(C2O4) + 2NH4(NO3)
What is the total iconic equation and net ionic equation of the reaction between calcium nitrate and ammonium oxalate?
Ca(NO3)2 + (NH4COO)2 = Ca(COO)2 + 2NH4NO3
Write and balance the molecular equation. You've done that. I've added the phases aq for aqueous and s for solid (meaning a ppt)
Ba(NO3)2(aq) + (NH4)2C2O4 (aq)→ Ba(C2O4) (s)+ 2NH4(NO3)(aq)
Separate the aq materials into ions like this but leave the solid since it doesn't dissolve.
Ba^2+(aq) + 2NO3^-(aq) + 2NH4^+(aq) + C2O4^2-(aq) ==> BaC2O4(s) + 2NH4^+(aq) + 2NO3^-(aq)
What you have now is the total ioinic equation. Now cancel the ions common to each side. 2NO3^- is on both sides so cancel. 2NH4^+ is on both sides so cancel. What's left is the net ionic equation.
Ba^2+(aq) + C2O4^2-(aq) ==> BaC2O4(s)
You do the others. Post any follow up questions here to help if you don't understand what I did above.
Oh, you've got some chemical reactions for me, huh? Alright, brace yourself for some chemistry comedy gold!
For the first reaction, the total iconic equation is:
Ba(NO3)2 + (NH4)2C2O4 → Ba(C2O4) + 2NH4(NO3)
Now, let's dive into the net ionic equation, where all the fun happens!
First, we need to split all the compounds into their individual ions:
Ba(NO3)2 → Ba^2+ + 2NO3^-
(NH4)2C2O4 → 2NH4^+ + C2O4^2-
Ba(C2O4) → Ba^2+ + C2O4^2-
2NH4(NO3) → 2NH4^+ + 2NO3^-
Now that we have everything separated, we can remove the spectator ions, which are the ones that appear on both sides of the equation:
The spectator ions are 2NO3^- and 2NH4^+.
And voila! The net ionic equation of the reaction between barium nitrate and ammonium oxalate is:
Ba^2+ + C2O4^2- → Ba(C2O4)
Now, onto the second reaction! Let's see what comedic chemistry awaits us.
The total iconic equation is:
Ca(NO3)2 + (NH4COO)2 = Ca(COO)2 + 2NH4NO3
Now, let's break it down and unleash our comedic curiosity.
First, we split everything up into ions:
Ca(NO3)2 → Ca^2+ + 2NO3^-
(NH4COO)2 → 2NH4^+ + 2COO^2-
Ca(COO)2 → Ca^2+ + 2COO^2-
2NH4NO3 → 2NH4^+ + 2NO3^-
Now, it's time to identify those spectator ions!
The spectator ions are 2NO3^- and 2NH4^+.
And there you have it, my hilarious human friend! The net ionic equation for the reaction between calcium nitrate and ammonium oxalate is:
Ca^2+ + 2COO^2- → Ca(COO)2
I hope that chemistry comedy routine put a smile on your face! If you have any more questions or need a dose of laughter, I'm here to entertain you!
The total ionic equation for the reaction between barium nitrate (Ba(NO3)2) and ammonium oxalate ((NH4)2C2O4) is:
Ba^2+ + 2NO3^- + 2NH4+ + C2O4^2- → BaC2O4 + 2NH4+ + 2NO3^-
The net ionic equation is obtained by removing the spectator ions (ions that appear on both sides of the equation unchanged), in this case, the nitrate ions (NO3^-) and ammonium ions (NH4+):
Ba^2+ + C2O4^2- → BaC2O4
Similarly, the total ionic equation for the reaction between calcium nitrate (Ca(NO3)2) and ammonium oxalate ((NH4COO)2) is:
Ca^2+ + 2NO3^- + 2NH4+ + COO^2- → Ca(COO)2 + 2NH4+ + 2NO3^-
And the net ionic equation is:
Ca^2+ + COO^2- → Ca(COO)2
To determine the total ionic equation and net ionic equation of a chemical reaction, we need to first understand the reactants and products involved.
Reactants:
- Barium nitrate (Ba(NO3)2)
- Ammonium oxalate ((NH4)2C2O4)
Products:
- Barium oxalate (Ba(C2O4))
- Ammonium nitrate (2NH4NO3)
1. Total Ionic Equation:
The total ionic equation represents all the species that are dissociated into ions in the reaction. To write the total ionic equation, we need to split all the reactants and products into their respective ions.
Reactants:
Ba(NO3)2 → Ba^2+ + 2NO3^-
(NH4)2C2O4 → 2NH4+ + C2O4^2-
Products:
Ba(C2O4) → Ba^2+ + C2O4^2-
2NH4NO3 → 2NH4+ + 2NO3-
Combining all the ions, the total ionic equation can be written as:
Ba^2+ + 2NO3^- + 2NH4+ + C2O4^2- → Ba^2+ + C2O4^2- + 2NH4+ + 2NO3-
2. Net Ionic Equation:
The net ionic equation focuses on the significant species involved in the reaction. To write the net ionic equation, we exclude the spectator ions - ions that appear on both sides of the equation and do not participate in the reaction.
In this case, the spectator ions are Ba^2+ and C2O4^2-. The net ionic equation is obtained by eliminating these spectator ions from the total ionic equation:
Net Ionic Equation:
2NO3^- + 2NH4+ → 2NH4+ + 2NO3-
Therefore, the net ionic equation for the reaction between barium nitrate and ammonium oxalate is:
2NO3^- + 2NH4+ → 2NH4+ + 2NO3-.
Now, for the reaction between calcium nitrate (Ca(NO3)2) and ammonium oxalate ((NH4COO)2):
Reactants:
Ca(NO3)2 → Ca^2+ + 2NO3^-
(NH4COO)2 → 2NH4+ + 2COO^2-
Products:
Ca(COO)2 → Ca^2+ + 2COO^2-
2NH4NO3 → 2NH4+ + 2NO3-
Total Ionic Equation:
Ca^2+ + 2NO3^- + 2NH4+ + 2COO^2- → Ca^2+ + 2COO^2- + 2NH4+ + 2NO3-
Net Ionic Equation:
2NO3^- + 2NH4+ + 2COO^2- → 2NH4+ + 2NO3-
Therefore, the net ionic equation for the reaction between calcium nitrate and ammonium oxalate is:
2NO3^- + 2NH4+ + 2COO^2- → 2NH4+ + 2NO3-.