Questions LLC
Login
or
Sign Up
Ask a New Question
Mathematics
Calculus
find the area of the region R that lies under y=√x (x+1), over 0≤x≤4
1 answer
I am not certain what is under the sqrt sign. Is is x, or x(x+1)
You can
ask a new question
or
answer this question
.
Related Questions
Find the area of the region that lies inside the first curve and outside the second curve.
r = 1 + cos(θ), r = 2 − cos(θ)
R is the first quadrant region enclosed by the x-axis, the curve y = 2x + a, and the line x = a, where a > 0. Find the value of
1. Let R be the region bounded by the x-axis, the graph of y=sqr(x) , and the line x=4 .
a. Find the area of the region R. b.
Use a graph to give a rough estimate of the area of the region that lies beneath the given curve. Then find the exact area.
y = 6
Let R be the region in the first quadrant under the graph of y=1/sqrt(x) for 4</=x</=9.
(a)Find the area of R. I took the
The region R is the region in the first quadrant bounded by the curves y = x^2-4x+4, x=0, and x=2.
Find a value h such that the
Region R is bounded by the functions f(x) = 2(x-4) + pi, g(x) = cos^-1(x/2 - 3), and the x axis.
a. What is the area of the
1. Let R be the region in the first quadrant enclosed by the graphs of y=4-X , y=3x , and the y-axis.
a. Find the area of region
let R be the region bounded by the x-axis, the graph of y=sqrt(x+1), and the line x=3.
Find the area of the region R
Sketch the region enclosed by the curves x=64−y^2 and x=y^2−64. Decide whether to integrate with respect to x or y. Then