i need serious help, I'm trying to plot table of values for sketching graph (parabola)for y=x^2-5x+3
xy values are 0,3 1,-1 2.5,-3.25 3,-3 4,-1 5,3 6,9
are these values correct, I'm having problems graphing.
Let me help you. Choose easy x
x= 0, 1, -1, 2, -2, 3, -3
then y will be
y=3, -1, 9, 9, 17, -3, 27
and your 2.5 looks like a good point to do for a sketch, (5/2, -3.25)
So am im posting the graph with 2.5 and -3.25?
como hago csct*sent
To verify if the given xy values are correct for the graph of the equation y = x^2 - 5x + 3, we can substitute each x-value into the equation and check if the calculated y-values match the given values.
Let's calculate the y-values for the given x-values:
For x = 0:
y = (0)^2 - 5(0) + 3 = 0 - 0 + 3 = 3 (matches the given value of 3)
For x = 1:
y = (1)^2 - 5(1) + 3 = 1 - 5 + 3 = -1 (matches the given value of -1)
For x = 2.5:
y = (2.5)^2 - 5(2.5) + 3 = 6.25 - 12.5 + 3 = -3.25 (matches the given value of -3.25)
For x = 3:
y = (3)^2 - 5(3) + 3 = 9 - 15 + 3 = -3 (matches the given value of -3)
For x = 4:
y = (4)^2 - 5(4) + 3 = 16 - 20 + 3 = -1 (matches the given value of -1)
For x = 5:
y = (5)^2 - 5(5) + 3 = 25 - 25 + 3 = 3 (matches the given value of 3)
For x = 6:
y = (6)^2 - 5(6) + 3 = 36 - 30 + 3 = 9 (matches the given value of 9)
Based on the calculations, the given xy values are correct for the equation y = x^2 - 5x + 3.
Now, you can plot these points on a graph and connect them to sketch a parabola.