When twice a number is decreased by 8, the result is the number increased by 7. How would you solve it and check answer into the original problem?
2x-8=x+7
you solve for x. THen,when you have x (the number), you go back and put it in the original equation above and see if both sides are equal.
The product that is twice a number and 5 isthe same as the difference of nine timesthe number and5/3.find the number
To solve this problem, we can translate the given information into an equation.
Let's say the number is represented by "x".
The first statement states "twice a number is decreased by 8." So, we can write this as "2x - 8".
The second statement states "the result is the number increased by 7." So, we can write this as "x + 7".
Now, we can set up an equation by equating these two expressions:
2x - 8 = x + 7
To solve this equation, we need to isolate the variable x by moving all terms with x to one side and constants to the other side.
2x - x = 7 + 8
Simplifying further:
x = 15
Therefore, the number is 15.
To check if this answer is correct, we can substitute the value of x back into the original problem and verify if both sides of the equation are equal.
Twice the number (2x) decreased by 8: 2(15) - 8 = 30 - 8 = 22
The number (x) increased by 7: 15 + 7 = 22
Both sides of the equation are equal (22 = 22), which confirms that the answer is correct.