Using the formula for the area of a triangle, A = 1/2 bh, find the area of this triangle pictured. The base is 2x + 16 and the height is 4x. I just don't know how to work the problem.
A = 1/2(2x + 16)(4x)
You have two unknowns, but only one equation.
6t-3
To find the area of the triangle, we can use the formula A = 1/2 bh, where A represents the area, b represents the base, and h represents the height.
In this case, the base of the triangle is given as 2x + 16, and the height is given as 4x.
So, substituting these values into the formula, we get:
A = 1/2 (2x + 16)(4x)
To simplify, we can distribute the 1/2 to both terms inside the parentheses:
A = 1/2 * 2x * 4x + 1/2 * 16 * 4x
Simplifying further:
A = 2x^2 + 8x^2
Combining like terms:
A = 10x^2
Therefore, the area of the triangle is 10x^2.
To find the area of the triangle, you need to substitute the given values into the formula A = 1/2 bh, where A represents the area, b represents the base, and h represents the height.
In this case, the base is given as 2x + 16, and the height is given as 4x.
So, plug these values into the formula:
A = 1/2 (2x + 16)(4x)
To simplify this expression, you need to distribute the 1/2 across the terms inside the parentheses:
A = (1/2)(2x)(4x) + (1/2)(2x)(16)
Next, simplify the expression:
A = (x)(4x) + (x)(16)
Now, multiply the terms:
A = 4x^2 + 16x
This is the final algebraic expression for the area of the triangle.