The formula A=12bh can be used to find the area of a triangle.
Solve the formula for b.
Now use your equation to find the base of a triangle with an area of 48 in2 and a height of 8 inches.
A = 1/2 bh
2A = bh
2A/h = b
To solve the formula A=12bh for b, we need to isolate the variable b on one side of the equation. Here are the steps:
1. Start with the equation A=12bh.
2. Divide both sides of the equation by 12 to get rid of the coefficient in front of b. This gives us A/12 = bh.
3. Now divide both sides of the equation by h. This gives us (A/12)h = b.
So, the formula to solve for b is b = (A/12)h.
Now, let's use this equation to find the base (b) of a triangle with an area of 48 in² and a height of 8 inches.
Given:
A = 48 in² (area of the triangle)
h = 8 inches (height of the triangle)
Substitute these values into the equation b = (A/12)h:
b = (48/12) * 8
b = 4 * 8
b = 32
Therefore, the base of the triangle is 32 inches.
To solve the formula A=12bh for b, we need to isolate b on one side of the equation.
Given:
A = 12bh
Step 1: Divide both sides of the equation by 12h:
A/(12h) = (12bh)/(12h)
Step 2: Simplify the right side of the equation:
A/(12h) = b
So, the equation is solved for b as:
b = A/(12h)
Now, we can find the base (b) of a triangle with an area of 48 in2 and a height of 8 inches.
Given:
A = 48 in2
h = 8 inches
Step 1: Substitute the given values into the equation:
b = A/(12h)
b = 48/(12 * 8)
Step 2: Simplify the equation:
b = 48/96
b = 0.5
Therefore, the base of the triangle is 0.5 inches.