An aqueous solution of ethanol is 3.05 M in ethanol, CH3CH2OH. Calculate the mole fraction of ethanol if the density of the solution is 0.964 g mL-1.
The basic defintion of mole fraction is the fraction of molecules of solute divided by total molecules.
molecules solute (assume 1 liter solution)= avag#*3.05
masswater= 964g-3.05*molmassEthanol)
molecules water=masswater/molmasswater * avag#
mole fraction= moleculessolute/totalmolecules * 100
thank you!!
To calculate the mole fraction of ethanol in the solution, we need to know the mass of ethanol and the mass of the solution.
First, we need to calculate the mass of the solution. We know the density of the solution, which is 0.964 g/mL. To convert this to grams, we multiply by the volume of the solution.
Let's assume we have 1 L of the solution, which is equivalent to 1000 mL.
Mass of solution = density of solution x volume of solution
= 0.964 g/mL x 1000 mL
= 964 g
Now, we need to calculate the mass of ethanol in the solution. We know the concentration of ethanol in the solution is 3.05 M. The molar mass of ethanol (C2H5OH) is approximately 46.07 g/mol.
Mass of ethanol = concentration x molar mass
= 3.05 mol/L x 46.07 g/mol
= 140.7835 g
Finally, we can calculate the mole fraction of ethanol.
Mole fraction of ethanol = Mass of ethanol / Mass of solution
= 140.7835 g / 964 g
≈ 0.146
Therefore, the mole fraction of ethanol in the solution is approximately 0.146.