the specific heat capacity of seawater is 3900 j/kg degrees celcius. how much energy is needed to heat 500g of seawater from 20 degrees celcius to 90 degrees celcius?
if not i need to know how to work it out
energy=mass*specificheat*changeintemp
= .5kg*3900j/kgC*(90-20)C
To calculate the energy needed to heat a substance, you can use the formula:
Q = mcΔT
Where:
Q is the energy in joules needed to heat the substance,
m is the mass of the substance in kilograms,
c is the specific heat capacity of the substance in joules per kilogram per degree Celsius (J/kg°C), and
ΔT is the change in temperature in degrees Celsius.
In this case, you want to calculate the energy required to heat 500g of seawater from 20°C to 90°C, using a specific heat capacity of 3900 J/kg°C.
First, convert the mass of seawater from grams to kilograms:
m = 500g / 1000 = 0.5 kg
Next, calculate the change in temperature:
ΔT = 90°C - 20°C = 70°C
Now, substitute the values into the formula:
Q = mcΔT
= 0.5 kg × 3900 J/kg°C × 70°C
= 136,500 J
Therefore, it would require 136,500 joules of energy to heat 500g of seawater from 20°C to 90°C.
To calculate the amount of energy needed to heat a certain amount of substance, you can use the equation:
Energy = mass × specific heat capacity × temperature change
In this case, the mass of the seawater is given as 500 grams (0.5 kg), the specific heat capacity of seawater is 3900 J/kg·°C, and the temperature change is from 20°C to 90°C.
Using the equation, we can calculate the energy required:
Energy = 0.5 kg × 3900 J/kg·°C × (90°C - 20°C)
Energy = 0.5 kg × 3900 J/kg·°C × 70°C
Energy = 0.5 × 3900 × 70 J
Energy = 136500 J (or 136.5 kJ)
Therefore, it would require approximately 136.5 kilojoules of energy to heat 500 grams of seawater from 20°C to 90°C.