An object with an initial velocity of 5 m/s accelerates uniformly for 15 s.
(a) If the final velocity is 37 m/s, what is the acceleration?
Vf=Vi+acceleration*time
solve for acceleration.
How far does the object travel during this time?
You need to memorize some formulas:
distance= Vi*time+ 1/2 * acceleration*time^2
or
distance=average velocity*time
=(1/2)(Vf+Vi)*time
putang ina niyo
To find the acceleration, we can use the equation of motion:
v = u + at
Where:
v = final velocity
u = initial velocity
a = acceleration
t = time
Given:
u = 5 m/s
v = 37 m/s
t = 15 s
Now, we can rearrange the equation to solve for acceleration (a):
a = (v - u) / t
Substituting the given values:
a = (37 m/s - 5 m/s) / 15 s
a = 32 m/s / 15 s
Evaluating the expression, we have:
a ≈ 2.133 m/s²
Therefore, the acceleration is approximately 2.133 m/s².