3x + 2y + 16x^3z + 6y =
ANSWER: 19x + 8y + 3z
again, incorrect
when you add/subtract terms they must be "like"
the variables and exponents do not change.
3x + 2y + 16x^3z + 6y
= 3x + 8y + 16x^3z
(the only terms that were "like" were the y terms )
If the problem has no typos, it can reduce to:
16x^3z + 8y + 3x
the question is i wrote it wrong
3x + 2y + 16x + 3z + 6y =
So what is your answer?
I see three kind of terms, x's , y's and z's
19x + 8y + 3z
Right.
To simplify the given expression, we need to combine like terms.
First, let's combine the terms with the same variable (x). We have 3x and 16x^3z. To combine them, we add their coefficients: 3x + 16x^3z = (3 + 16x^2z)x.
Next, let's combine the terms with the same variable (y). We have 2y and 6y. To combine them, we add their coefficients: 2y + 6y = 8y.
Finally, we have the simplified expression: (3 + 16x^2z)x + 8y + 3z.
So, the answer is 19x + 8y + 3z.