what fraction of the numbers from 1 to 1000 have the digit 7 as the least one of the digits
Of one-digit numbers (1 to 9): 1
Of two-digit numbers (10 to 99): 10 + 8 = 18
Of three-digit numbers: (100 to 999): 100 + 80 + 9x8 = 252
Of 4-digit numbers (1000 only): 0
Total: 271
nuber less than 32 am a multiple of 3 the digits of my number add up to 6
How can you make the sum of 12 by using only 3 digit odd numbers and are not used twice?
To find the fraction of numbers from 1 to 1000 that have the digit 7 as one of the least significant digits, we can count the number of such numbers and then divide it by the total number of numbers from 1 to 1000.
We can solve this problem by considering each place value (ones, tens, hundreds) separately.
1. Ones place:
There are 10 possible digits for the ones place (0 to 9). Out of these, only one digit is 7. So, the fraction of numbers with 7 as the ones place digit is 1/10.
2. Tens place:
Again, there are 10 possible digits for the tens place (0 to 9). In this case, the digit 7 can appear in any of the 10 positions (tens place can be 7, 17, 27, ..., 97). So, the fraction of numbers with 7 as the tens place digit is 10/100.
3. Hundreds place:
Similar to the above, there are 10 possible digits for the hundreds place (0 to 9). The digit 7 can appear in any of the 10 positions (hundreds place can be 7, 107, 207, ..., 907). So, the fraction of numbers with 7 as the hundreds place digit is 10/1000.
Now, to find the overall fraction, we multiply the fractions representing each place value:
Fraction = (1/10) * (10/100) * (10/1000) = 1/1000
Therefore, the fraction of numbers from 1 to 1000 that have the digit 7 as one of the least significant digits is 1/1000.