how long does it take a 19kW steam engine to do 6.8x10^7 J of work?
I tried that and I'm still not getting the right answer. Any other suggestions?
To determine how long it takes for a 19kW steam engine to do 6.8x10^7 J of work, we need to calculate the time using the power and the amount of work done.
First, let's convert the power from kilowatts (kW) to watts (W). Since 1 kW is equal to 1000 W, the steam engine has a power of 19,000 W.
We know that power (P) is the rate at which work (W) is done, and can be calculated as:
P = W/t,
where P is the power in watts, W is the work done in joules, and t is the time in seconds.
Rearranging this equation to find the time (t), we get:
t = W/P.
Now we can substitute the given values:
W = 6.8x10^7 J (work done)
P = 19,000 W (power)
t = (6.8x10^7 J) / (19,000 W).
To find the time, let's calculate this:
t = 6.8x10^7 J / 19,000 W
t ≈ 3,579.47 seconds.
Therefore, it takes approximately 3,579.47 seconds for the 19kW steam engine to do 6.8x10^7 J of work.
power= work/time
timeinseconds= work in Joules/powerinKwatts