Consider the function f(x) = 2xโˆ’1%0D%0A๐‘“%0D%0A(%0D%0A๐‘ฅ%0D%0A)%0D%0A %0D%0A=%0D%0A %0D%0A2%0D%0A๐‘ฅ%0D%0Aโˆ’%0D%0A1%0D%0AWhat is the output if the input is x=โˆ’3%0D%0A๐‘ฅ%0D%0A=%0D%0Aโˆ’%0D%0A3%0D%0A ?%0D%0A%0D%0A(1 point)%0D%0Af(x)=%0D%0A๐‘“%0D%0A(%0D%0A๐‘ฅ%0D%0A)%0D%0A=%0D%0A

To find the output when x = -3, we plug x = -3 into the function f(x) = 2x - 1.

f(-3) = 2(-3) - 1
f(-3) = -6 - 1
f(-3) = -7

Therefore, the output when x = -3 is -7.