Find any points of discontinuity for the rational function.%0D%0A%0D%0Ay=x−2x2−4x+3%0D%0A%0D%0A=%0D%0A%0D%0A−%0D%0A2%0D%0A%0D%0A2%0D%0A−%0D%0A4%0D%0A%0D%0A+%0D%0A3%0D%0A(1 point)%0D%0AResponses%0D%0A%0D%0Ax=3, x=1%0D%0A%0D%0A=%0D%0A3%0D%0A,%0D%0A %0D%0A%0D%0A=%0D%0A1%0D%0Ax=3, x=1%0D%0A%0D%0A=%0D%0A3%0D%0A,%0D%0A %0D%0A%0D%0A=%0D%0A1%0D%0A%0D%0Ax=−3, x=1%0D%0A%0D%0A=%0D%0A−%0D%0A3%0D%0A,%0D%0A %0D%0A%0D%0A=%0D%0A1%0D%0Ax=−3, x=1%0D%0A%0D%0A=%0D%0A−%0D%0A3%0D%0A,%0D%0A %0D%0A%0D%0A=%0D%0A1%0D%0A%0D%0Ax=1, x=−6%0D%0A%0D%0A=%0D%0A1%0D%0A,%0D%0A %0D%0A%0D%0A=%0D%0A−%0D%0A6%0D%0Ax=1, x=−6%0D%0A%0D%0A=%0D%0A1%0D%0A,%0D%0A %0D%0A%0D%0A=%0D%0A−%0D%0A6%0D%0A%0D%0Ax=−2

Points of discontinuity for the rational function y=x−2x2−4x+3 are x=3 and x=1.