Plant Types: A, B, C, D, E
Number of seedling's 100, 140, 80, 60, 40
A farmer conducted an inventory on his two square kilometers of rainforest; the results are in the table. He plans on randomly selecting a seedling to seedling to experiment on when he goes back to the forest. What is the probability that he will randomly pick a type B plant? write your answer in the simplest form of a fraction
The total number of seedlings is 100 + 140 + 80 + 60 + 40 = 420.
The number of type B seedlings is 140.
The probability of randomly selecting a type B seedling is 140/420 = 1/3.
So, the probability of randomly picking a type B plant is 1/3.
Out of the 2,500 bulbs tested, 2,200 bulbs burnt out after more than 1,500 hours of use.
The probability that a bulb will burn out after more than 1,500 hours is calculated as the ratio of the number of bulbs burnt out after more than 1,500 hours to the total number of bulbs tested.
Probability = (Number of bulbs burnt out after more than 1,500 hours) / (Total number of bulbs tested)
Probability = 2,200 / 2,500
Probability = 0.88
Therefore, the likelihood that the light bulb from company X will burn for more than 1,500 hours is 0.88 or 88%.
Company X tested its light bulbs to see how long they would last. On a production line, 2,500 bulbs were taken and tested. The department in charge reported that out of 2,500 bulbs, there were 2,200 bulbs burnt out after more than 1,500 hours of use. Lucy purchased a light bulb company X. What is the likelihood that it will burn for more than 1,500 hours? write your answer in a decimal form.
the letter tiles C, A, R, E, and S are placed in a box. without looking, Jorelle picks a letter tile from the box and records the result before placing it back. He repeats the procedure 100 times and observes the following results:
Outcomes: C, A, R, E, S
Frequency: 20, 25, 30, 10, 15
Based on the observed frequency, what is the probability that Jorelle will pick a letter R? The answer should be in percent form.
The total number of outcomes is 20 + 25 + 30 + 10 + 15 = 100.
The frequency of picking the letter R is 30.
The probability of picking the letter R is calculated as:
Probability = (Frequency of picking R) / (Total number of outcomes)
Probability = 30 / 100
Probability = 0.30
To convert this probability to a percentage, we multiply by 100:
0.30 * 100 = 30%
Therefore, based on the observed frequency, the probability that Jorelle will pick the letter R is 30%.
Outcomes 2, 4, 6, 8, 10, 12
Frequency 10, 9, 6, 15, 13, 8
Jede tossed a cube with faces numbered with 2, 4, 6, 8, 10, and 12. the result are recorded in the table. What is the largest discrepancy between the experimental and the expected probability of this experiment? The answer needs to be in percent form to the nearest whole number.
To find the largest discrepancy between the experimental and the expected probability, we need to calculate both probabilities for each outcome.
The total number of outcomes is 10 + 9 + 6 + 15 + 13 + 8 = 61.
The expected probability for each outcome is 1/6 since there are 6 equally likely outcomes.
Expected probability for each outcome = 1/6 ≈ 0.1667
Now, we can calculate the expected frequency for each outcome:
Expected frequency = Expected probability * Total number of outcomes
Expected frequency = 1/6 * 61 ≈ 10.167
Now, let's calculate the experimental probability and find the largest discrepancy:
| Outcome | Frequency | Experimental Probability | Expected Probability | Discrepancy |
|---------|-----------|--------------------------|----------------------|------------|
| 2 | 10 | 10/61 ≈ 0.1639 | 1/6 ≈ 0.1667 | 0.0028 |
| 4 | 9 | 9/61 ≈ 0.1475 | 1/6 ≈ 0.1667 | 0.0192 |
| 6 | 6 | 6/61 ≈ 0.0984 | 1/6 ≈ 0.1667 | 0.0683 |
| 8 | 15 | 15/61 ≈ 0.2459 | 1/6 ≈ 0.1667 | 0.0792 |
| 10 | 13 | 13/61 ≈ 0.2131 | 1/6 ≈ 0.1667 | 0.0464 |
| 12 | 8 | 8/61 ≈ 0.1311 | 1/6 ≈ 0.1667 | 0.0356 |
The largest discrepancy is for the outcome 8, with a discrepancy of 0.0792 or 7.92%. Therefore, to the nearest whole number, the largest discrepancy is 8%.
do the same question but this time write your answer in 3 decimal places, rounded to the nearest thousandth.
To find the largest discrepancy between the experimental and the expected probability, we need to calculate both probabilities for each outcome.
The total number of outcomes is 10 + 9 + 6 + 15 + 13 + 8 = 61.
The expected probability for each outcome is 1/6 since there are 6 equally likely outcomes.
Expected probability for each outcome = 1/6 ≈ 0.1667
Now, we can calculate the expected frequency for each outcome:
Expected frequency = Expected probability * Total number of outcomes
Expected frequency = 0.1667 * 61 ≈ 10.167
Now, let's calculate the experimental probability and find the largest discrepancy:
| Outcome | Frequency | Experimental Probability | Expected Probability | Discrepancy |
|---------|-----------|--------------------------|----------------------|------------|
| 2 | 10 | 10/61 ≈ 0.1639 | 1/6 ≈ 0.1667 | 0.0028 |
| 4 | 9 | 9/61 ≈ 0.1475 | 1/6 ≈ 0.1667 | 0.0192 |
| 6 | 6 | 6/61 ≈ 0.0984 | 1/6 ≈ 0.1667 | 0.0683 |
| 8 | 15 | 15/61 ≈ 0.2459 | 1/6 ≈ 0.1667 | 0.0792 |
| 10 | 13 | 13/61 ≈ 0.2131 | 1/6 ≈ 0.1667 | 0.0464 |
| 12 | 8 | 8/61 ≈ 0.1311 | 1/6 ≈ 0.1667 | 0.0356 |
The largest discrepancy is for the outcome 8, with a discrepancy of 0.0792. Therefore, rounded to three decimal places, the largest discrepancy is 0.079.