Use the table to answer the question.

Plant Types A B C D E
Number of Seedlings 100 140 80 60 40
A farmer conducted an inventory on his two square kilometers of rainforest; the results are in the table. He plans on randomly selecting a seedling to experiment on when he goes back to the forest. What is the probability that he will randomly pick a type B plant? Write your answer in the simplest form of a fraction.

(1 point)

The total number of seedlings is 420 (100+140+80+60+40). The number of type B seedlings is 140.

Therefore, the probability of picking a type B plant is:

140/420

Simplifying this fraction by dividing both the numerator and denominator by 140 (the greatest common factor), we get:

1/3

Therefore, the probability of picking a type B plant is 1/3 or approximately 0.333.

The letter tiles C, A, R, E, and S are placed in a box. Without looking, Jorelle picks a letter tile from the box and records the result before placing it back. He repeats the procedure 100 times and observes the following results:

Outcomes C A R E S
Frequency 20 25 30 10 15
Based on the observed frequency, what is the probability that Jorelle will pick a letter R? The answer should be in percent form.

(1 point)

The frequency of letter R is 30, out of a total of 100 picks.

Therefore, the probability of picking a letter R is:

30/100 = 0.3

To convert this decimal to a percentage, we multiply by 100:

0.3 x 100 = 30%

Therefore, the probability of picking a letter R is 30%.

Use the table to answer the question.

Outcomes 2 4 6 8 10 12
Frequency 10 9 6 15 13 8
Jede tossed a cube with faces numbered with 2, 4, 6, 8, 10, and 12. The results are recorded in the table. What is the largest discrepancy between the experimental and the expected probability of this experiment? The answer needs to be in percent form to the nearest whole number.

(1 point)

There are six possible outcomes and each outcome has a probability of 1/6 if the cube is fair.

Therefore, the expected probability for each outcome is:

1/6 = 0.1667 (rounded to four decimal places)

To calculate the experimental probability for each outcome, we divide the frequency by the total number of trials:

Experimental probability = frequency/total trials

For example, the experimental probability of getting a 2 is:

10 / (10+9+6+15+13+8) = 0.1923 (rounded to four decimal places)

We can calculate the experimental probability for each outcome using the same formula.

To find the largest discrepancy between the experimental and expected probability, we need to find the absolute difference between the two for each outcome and then find the largest value.

For example, the absolute difference for getting a 2 is:

|0.1923 - 0.1667| = 0.0256 (rounded to four decimal places)

We can calculate the absolute difference for each outcome using the same formula.

The largest discrepancy is between the experimental probability of getting an 8 and the expected probability.

The expected probability of getting an 8 is 0.1667.

The experimental probability of getting an 8 is:

15 / (10+9+6+15+13+8) = 0.2885 (rounded to four decimal places)

The absolute difference is:

|0.2885 - 0.1667| = 0.1218 (rounded to four decimal places)

Therefore, the largest discrepancy between the experimental and the expected probability is 12% (rounded to the nearest whole number).

Use the table to answer the question.

Outcomes K I N D
Frequency 120 140 105 135
A spinner is divided into 4 sections labeled as K, I, N, D. Xavier reproduced the wheel and uses a computer to simulate the outcomes of 500 spins. What is the approximate probability that the spinner will stop on a consonant on the next spin?

(1 point)

There are two consonants on the spinner, K and N. The total number of outcomes in one spin is 4.

The probability that the spinner will stop on a consonant in one spin is:

P(consonant) = number of consonants / total number of outcomes

P(consonant) = 2/4 = 0.5

This means that the probability of getting a consonant on one spin is 0.5 or 50%.

Since Xavier simulated 500 spins, we can estimate the number of spins that will result in a consonant by multiplying the probability by the total number of spins:

Number of spins with a consonant = P(consonant) x Total number of spins

Number of spins with a consonant = 0.5 x 500

Number of spins with a consonant = 250

Therefore, the approximate probability that the spinner will stop on a consonant on the next spin is 250/500, or 0.5 (or 50%)

The letter tiles C, A, R, E, and S are placed in a box. Without looking, Jorelle picks a letter tile from the box and records the result before placing it back. He repeats the procedure 100 times and observes the following results:

Outcomes C A R E S
Frequency 20 25 30 10 15
Based on the observed frequency, develop a probability model for this experiment. Express the probability in decimal form, rounded to the nearest hundredth.

(1 point)

The probability of selecting each letter can be calculated by dividing the frequency of that letter by the total number of trials, which is 100 in this case.

The probability of selecting C is:

P(C) = 20/100 = 0.20

The probability of selecting A is:

P(A) = 25/100 = 0.25

The probability of selecting R is:

P(R) = 30/100 = 0.30

The probability of selecting E is:

P(E) = 10/100 = 0.10

The probability of selecting S is:

P(S) = 15/100 = 0.15

So the probability model for this experiment is:

P(C) = 0.20
P(A) = 0.25
P(R) = 0.30
P(E) = 0.10
P(S) = 0.15

Probability of Chance Events Quick Check

4 of 54 of 5 Items

Question
Use the tables to answer the question.

Simon’s Results

Number of White Balls Selected Number of Red Balls Selected
Bowl A 5 15
Bowl B 16 4
Clark’s Results

Number of White Balls Selected Number of Red Balls Selected
Bowl A 45 55
Bowl B 60 40
Bowls A and B contain a number of white and red balls. Simon and Clark repeatedly selected a ball from both bowls and recorded the results in a table. Whose results will give you a better indication about the proportion of white and red balls in each bowl? Explain your answer.

(1 point)